The x and y coordinates of the track are related in dimensionless units by $y=\frac{x^2}{4}$, where the positive y-axis is in the vertical downward direction. As the particle slides down the track, what is its tangential acceleration?

- $0$
- $g$
- $\frac{gx}{2}$
- $\frac{gx}{\sqrt{x^2+4}}$
- $\frac{gx^2}{\sqrt{x^2+16}}$

Solution :

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